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Êóðñîâàÿ ðàáîòà: Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â òà åêîíîì³÷íî¿ åôåêòèâíîñò³ ïåðåâåçåíü
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Êóðñîâàÿ ðàáîòà: Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â òà åêîíîì³÷íî¿ åôåêòèâíîñò³ ïåðåâåçåíü

                                                                                                                     

2.1.  Ðîçðàõóíîê ê³ëüêîñò³ âïëèâ³â

                                              

2.1.1. ʳëüê³ñòü êàï³òàëüíèõ ðåìîíò³â

                                              

Nêð =  Lçàã  =2

            Lêð

2.1.2. ʳëüê³ñòü ÒÎ-2

                                              

Nòî-2     =  Lçàã  - -  Nêð = 59

                Lòî-2

2.1.3. ʳëüê³ñòü TO-I

                                  

Nòî-1 =   Lçàã  - -  (Nêð+Nòî-2) = 121

                Lòî-2                                

2.1.4. ʳëüê³ñòü ÙΠ

                                  

Nùî = Lçàã        =3176

            Läîá

2.2.    Òðóäîì³ñòê³ñòü îáñëóãîâóâàíü                                          

2.2.1. Òðóäîì³ñòê³ñòü ÙΠ  

                                  

Òùî = Nùî*tùî = 2382 (÷îë-ã)

2.2.2. Òðóäîì³ñòê³ñòü TO-I  

                                  

Òòî-1 = tòî-1*Nòî-1 = 231,1 (÷îë-ã)

2.2.3. Òðóäîì³ñòê³ñòü ÒÎ-2 

                                  

Òòî-2     =  tòî-2*Nòî-2 =509,2(÷îë-ã)

2.2.4. Òðóäîì³ñòê³ñòü ÏÐ

                                              

Òïð = tïð*Lçàã/1000 = 4887,1(÷îë-ã)

2.2.5. Çàãàëüíà òðóäîì³ñòê³ñòü

                                              

Òçàã = Òùî+Òòî-1+Òòî-2 +Òïð = 8009,4 (÷îë-ã)  


3.×ÈÑÅËÜͲÑÒÜ ÏÅÐÑÎÍÀËÓ                                      

                                                                      

3.1. ×èñåëüí³ñòü âî䳿⠠                                                                

Nâ =   1,05*ÀÃå =23(÷îë.)  

           ÔÐ×*Êïò                                                                   

äå:

1,05   - êîåô³ö³ºíò, ùî âðàõîâóº ï³äãîòîâ÷î-çàêëþ÷íèé ÷àñ;                                                  

Êïò- êîåô³ö³ºíò, ùî âðàõîâóº ïðîäóêòèâí³ñòü ïðàö³, ( Êïò = 1.05)

ÔÐ×1â - ôîíä ðîáî÷îãî ÷àñó,ãîä                                                             

ÔÐ×1â = (Äê - Äâ³äï - Äñâ – Ääåðæ.îáîâ - Äõâîð - Äâèõ) * Òð.ä- Äïñ * t1=1695 (ã)                                  

äå:                                                                 

Äâ³äï -      äí³ â³äïóñòêè [ùîð³÷íà äîäàòêîâà â³äïóñòêà âñòàíîâëåíà òðèâàë³ñòþ 24 êàëåíäàðíèõ äí³ äëÿ âñ³õ ïðàöþþ÷èõ ÀÒÏ,                                                              

äëÿ âî䳿â âñòàíîâëþºòüñÿ ùå äîäàòêîâà ùîð³÷íà â³äïóñòêà çà îñîáëèâèé õàðàêòåð ðîáîòè,ÿêà âñòàíîâëåíà â³ä 4 äî 7 êàëåíäàðíèõ äí³â (çã³äíî óìîâ,âèçíà÷íèõ ó Êîëåêòèâíîìó äîãîâîð³ ÀÒÏ)                                                                  

Äñâ                - äí³ ñâÿòêîâ³ ïåâíîãî ðîêó;                                                            

Ääåðæ.îáîâ  - äí³ íåÿâêè íà ðîáîòó â çâ'ÿçêó ç âèêîíàííÿì äåðæàâíèõ îáîâ'ÿçê³â, (3äí)

Äõâîð            - äí³ íåÿâêè íà ðîáîòó ç ÷è õâîðîáè ³íøèõ ïîâàæíèõ ïðè÷èí, Äõâîð = 5 äí.; 

Äâèõ              - äí³ âèõ³äí³ ïåâíîãî ðîêó;                                                              

Tp ä                - íîðìàòèâíà òðèâàë³ñòü ðîáî÷îãî äíÿ,ãîä (8 ãîä.)                         

t1                    - ÷àñ çì³íè íà ÿêèé ñêîðî÷åíèé ðîáî÷èé äåíü ó ñâÿòêîâ³ äí³, ti = 1 ì;            

Äïñ                 - äí³ ïåðåäñâÿòêîâ³ ïåâíîãî ðîêó.                                                             

3.2. ×èñåëüí³ñòü ðåìîíòíèê³â                                                                 

Nð.ð.=         Tçàã            =  4(÷îë)

                ÔÐ×ð*Êïò

           

ÔÐ×ð=  (Äê – Äâ³äï.ð - Äñâ – Ääåðæ.îáîâ - Äõâîð - Äâèõ) * Òð.ä- Äïñ * t1=1743

           

3.3. ×èñåëüí³ñòü äîïîì³æíèõ ðîá³òíèê³â                                                          

Νäîï. = 0,2 * Νρ.ρ. = 1 (÷îë),                                                             

äå:                                                                 

0,2 - 20% â³ä ÷èñåëüíîñò³ ðåìîíòíèê³â                                                                                      

3.4. ×èñåëüí³ñòü êåð³âíèê³â ³ ñïåö³àë³ñò³â:                                                                     

Nêep = (Nâ + Näîï +Νρ,ρ.) * 0,1 = 3 (÷îë)                                                                 

                                                                      

äå:                                                                 

0,1 - 10% â³ä ñóìè ê³ëüêîñò³ âî䳿â, ðåìîíòíèê ³ äîïîì³æíèõ                                                             

ðîá³òíèê³â                                                               

3.5. ×èñåëüí³ñòü ïåðñîíàëó ÀÒÏ                                                 

                                                          

Nïep = Nâ+ Np.p + Νκ+Näîï + Nêep =31 (÷îë)                                               


4.ÂÈÒÐÀÒÈ ÍÀ ÎÏËÀÒÓ ÏÐÀÖ²                                                                     

                                                                                                                                

4.1.Îñíîâíà çàðîá³òíà ïëàòà âî䳿â, ùî ïðàöþþòü â³äðÿäíî.                                                                                                                              

                                                                                                                                

4.1.1. ³äðÿäíà çàðîá³òíà ïëàòà âî䳿â âàíòàæíèõ àâòîìîá³ë³â:           

ÎÔÇÏ â = (Qp * Ñò + Pp * Cò.êì) * Êâ + ÀÃï-ç * Ñãîä = 74544,4 (ãðí.)

äå:

Ñãîä      - òàðèôíà ãîäèííà ñòàâêà âîä³ÿ III êëàñó (1,684ãðí)                                                    

Êâ         - êîåô³ö³ºíò, ùî âðàõîâóº êëàñ âàíòàæó (1,0)

ÀÃï-ç    - àâòîìîá³ë³ ãîäèíè ï³äãîòîâ÷î-çàêëþ÷í³,                                                                     

Ñò.êì            - â³äðÿäíà ðîçö³íêà çà 1 òîíî-ê³ëîìåòð.

                                                                      

ÀÃï-ç = 0,05 * ÀÃå = 1952,9  (àâòî-ã),

                                                                                             

äå:                                                                                                                                                   

0,05    - 5% â³ä àâòîìîá³ëå ãîäèí â åêñïëóàòàö³¿;                                               

Ñò      - â³äðÿäíà ðîçö³íêà çà îäíó òîíó ïåðåâåçåíîãî âàíòàæó;

                                  

Cò =  Ñãîä * Í÷àñò /60 = 0,0017   (ãðí)

Ñò.êì     =Ñãîä*Í÷àñ.ò.êì  =  0,019 (ãðí)

äå:     Í÷àñ.ò       - íîðìà ÷àñó çà òîíó ïåðåâåçåíîãî âàíòàæó;

          Íâð.ò.êì   - íîðìà ÷àñó çà 1òîíî-ê³ëîìåòð;     

Í÷àñ.ò  =     tí-ð    =  0,06 (ð³ê)                                                                                                                                 qí* γ

                                   1

Íâð.ò.êì  =                                     =  0,011

                      Vòð* βð*qí* γ

4.2. Äîäàòêîâà çàðîá³òíà ïëàòà

4.2. 1 . Íàäáàâêà çà êëàñí³ñòü :                                                                             

                                                                                 

Hêë = Ñãîä * ÔÐ×1â (0,25*Νâ² + 0,1 * Nâ²²) = 7564,1 (ãðí)                                                                           

äå:   Νâ² , Nâ²²  - ÷èñåëüí³ñòü âî䳿â â³äïîâ³äíî ² ³ II êëàñ³â;                                                                                                                                     

0,25 - 25% - äîïëàòà âîä³ÿì ² êëàñó;                                                                    

0, 1 - 1 0% - äîïëàòà âîä³ÿì II êëàñó;                                                                  

                                                                      

Νâ² = Nâ *ಠ  = 7 (÷îë.)                                                                

Νâ²² =            Nâ *ಲ = 9 (÷îë.)

           

à³, àö - â³äñîòîê âî䳿â â³äïîâ³äíî ² ³ II êëàñ³â,                                                              

à²=30%,ಲ=40%

4.2.2. Ïðåì³ÿ âîä³ÿì âàíòàæíèõ àâòîìîá³ë³â çà ñâîº÷àñíå ³ ÿê³ñíå âèêîíàííÿ çàâäàíü:                                                                                                                            

Ï = àïð * ÎÔÇÏ â /100 = 22363,3 (ãðí.)

äå:      

àïð - â³äñîòîê ïðå쳿 30%

4.3. Äîïëàòà çà êåð³âíèöòâî áðèãàäîþ

Äáð = ÔÐ× * Ñãîä * Ν6ρ * Êáð = 1712,6 (ãðí)                                                         

äå:                                                     

Ν6ρ - ê³ëüê³ñòü áðèãàä;                                                      

                                                          

Ν6ρ =   Nâ   =  3

            náð

                                              

náð=8                                                                                                            

Ñòðàíèöû: 1, 2, 3, 4, 5, 6, 7, 8, 9

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